California Real Estate Practice Exam

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Prepare for the California Real Estate Exam. Study with flashcards and multiple-choice questions, each question includes hints and explanations. Get ready to ace your exam!

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A building has two separate sections, each with internal dimensions of 25' width by 80' depth. The dividing center wall, running from front to back, is 12" thick, and all exterior walls are 6" thick. How much land does the building cover?

4,043 sq. ft.
4,061 sq. ft.
4,212 sq. ft.
4,366 sq. ft.

The correct answer is: 4,043 sq. ft.

To determine how much land the building covers, we must calculate the total exterior dimensions of the building, taking into account the thickness of the walls and the interior dimensions. The building has two sections, each with internal dimensions of 25 feet width by 80 feet depth. Therefore, the total internal width of both sections is 25 feet + 25 feet, which equals 50 feet. However, we need to account for the dividing wall, which is 12 inches (1 foot) thick. Starting with the total width calculation: - The width of both sections combined is 50 feet. - Since the wall between them is 1 foot thick, the overall exterior width becomes 50 feet + 1 foot = 51 feet. Next, we consider the depth of the building, which remains 80 feet, as the wall thickness does not affect the overall depth. Now we can calculate the total area that the building covers by multiplying the exterior width by the exterior depth: - Exterior Area = Exterior Width × Depth = 51 feet × 80 feet = 4,080 square feet. The thickness of the exterior walls (which are 6 inches or 0.5 feet thick) needs to be added to the calculation for the overall